## Walter vs Lasker

Max Walter vs Lasker, Ostrava, 1923

Lasker with the black wins in 3.

FEN: `4r1k1/3n1ppp/4r3/3n3q/Q2P4/5P2/PP2BP1P/R1B1R1K1 b - - 0 1`

Roll over to show the solution:`1... Rg6+ 2. Kh1 Qxf3+ 3. Bxf3 Rxe1#`

Max Walter vs Lasker, Ostrava, 1923

Lasker with the black wins in 3.

FEN: `4r1k1/3n1ppp/4r3/3n3q/Q2P4/5P2/PP2BP1P/R1B1R1K1 b - - 0 1`

Roll over to show the solution:`1... Rg6+ 2. Kh1 Qxf3+ 3. Bxf3 Rxe1#`

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Re6-g6+

Be1-g5 Qh5xg5+

Kg1-h1 Qg5-g2#

2. … qf3+

The analysis is:

1…Rg3+

2. Kh1 (if 2. Kf1, then 2…Qh3#)

2…Qxf3+! (the key move)

3. Bxf3 (forced) Rxe1#

The combination is based on the “weak last rank” theme. Due to the presence of White’s Bc1, the Rooks are not “connected”, thus Re1 is vulnerable. Re1 also is the target of the connected Black’s Rooks on e-file, the only piece that prevents White’s Rooks to enter into the “weak last rank” is the Be2. Also, the pawn skeleton on White’s kingside is “open”, leaving the King exposed to direct checks.

Last but not least, since it’s Black to play, means that he has the “initiative”.

Note that White is up three pawns in material, but his position is lost. The (always spectacular) Queen sacrifice on f3 is the move that “removes the defender” Be2 and allows the final blow on the “last rank”.

Nice combination!

To complete the picture, the analysis is:

1) Rg6+ (not Rg3, as I typed erroneously previously).

A) 2. 2. Kh1 (if 2. Kf1, then 2…Qh3#)

2…Qxf3+! (the key move)

3. Bxf3 (forced) Rxe1#

B) 2. Bg5 Qxg5+

3. Kh1 (or Kf1) Qg2#

B, as stated by Carlos, also.

the answer is:

Re6-g6+

Bc1-g5 Qh5xg5+

Kg1-h1 Qg5-g2#

Re6-g6+

2. Bc1-g5 Qh5xg5+

3. Kg1-h1 Qg5-g2#

1. ———, Re6-g6+

2. Bc1-g5, Qh5xg5+

3. Kg1-f1, Qg5-g2#